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NCERT Mathematics Solutions for class 9 Chapter 9 CIRCLES Ex. 9.1

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KEY Concept For Chpt. 9.1 Circles

Circle

A circle is the collection of all points, which are equidistant from a fixed point in the plane.


Radius

Any line segment starting at the centre of the circle and joining anywhere on the border on the circle is a Radius of Circle.


Chord

Any line segment that’s both endpoints (starting and ending) anywhere on the border on the circle is known as Chord .


Diameter

The longest chord of a circle and which passes through the centre of the Circle is a Diameter of the circle.


Arc

An arc is a smooth curve joining two points anywhere on the border on the circle . A continuous piece of a circle is Arc of the circle .


Circumference

It is the length of the circle if we open and straightened out to make a line segment.



Segment

The region between a chord and either of its arcs is called a segment of the circular region or simply a segment of the circle. It could be a major or minor segment.


Sector

The region between an arc and the two radii, joining the centre to the end points of the arc is called a sector. It could be a major or minor sector.


Theorem 9.1

Equal chords of a circle subtend equal angles at the centre.


Theorem 9.2

If the angles subtend by two chords of a circle at the centre ( corresponding centers ) are equal, then the chords must be equal.



Circles ⇒⇒ Exercise 9.1

Question 1

Recall that two circles are congruent if they have the same radii. Prove that equal chords of congruent circles subtend equal angles at their centers.


Solution :



Given : Two circles having centres O and O’ and having equal radius.


Let AB and CD be the equal chords of 2 congruent circles.

AB = CD


We want to prove that the angles subtended by the chords at the centers are equal, i.e.,

$\angle $ AOB = $\angle $ CO’D


In Δ AOB and Δ CO'D

We know that the radius of both the circles are equal. So ,


OA = O’C

OB = O’D


( Equal radius of the congruent circles )


AB = CD


( Given equal chords )


Since all three corresponding sides of Δ AOB and Δ CO'D are equal, the two triangles are congruent by the SSS congruence criterion.


Δ AOB ≅ Δ CO'D


By the property of Corresponding Parts of Congruent Triangles (CPCT), the corresponding angles of the congruent triangles must be equal. Therefore,


∴ $\angle $ AOB = $\angle $ CO’D


Hence Proved.


Question 2

Prove that if chords of congruent circles subtend equal angles at their centers, then the chords are equal.


Solution :



Given that two circles are congruent with centers O and O' and having equal radius..

Let chords of congruent circles subtend equal angles at their centres.

$\angle $ AOB = $\angle $ CO’D


To Prove: AB and CD be the equal chords of 2 congruent circles.

AB = CD


In Δ AOB and Δ CO'D

We know that the radius of both the circles are equal. So ,

OA = O’C

( Equal radius of the congruent circles )


$\angle $ AOB = $\angle $ CO’D

( Chords subtend equal angles at centre )


OB = O’D

( Equal radius of the congruent circles )


Since two corresponding sides and the included angle of Δ AOB and Δ CO'D are equal, the two triangles are congruent by the SAS congruence criterion.


Δ AOB ≅ Δ CO'D


By the property of Corresponding Parts of Congruent Triangles (CPCT), the corresponding angles of the congruent triangles must be equal. Therefore,


∴ AB = CD


Hence Proved.


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